Alloys Loaded Must

I have an engineering question, please help me, I'm in trouble, and I'm Tring really hard?

Structural mm long, 250 members will be capable of withstanding a load of 44,400 N without undergoing plastic deformation. Provide the following information from brass, steel, aluminum and titanium alloy yield, MPa Density, g / cm 3 345 Brass 690 7.9 Aluminum 8.5 Steel 275 2.7 Titanium 480 4.5 Classification of materials at least for the greater weight of structural members.

Suppose the insured must bear a simple axial loading. Therefore, you can report the stress fibers by the definition of stress: sigma = F / A range of A, the cross section: A = F / Sigma to find the weight of the material, multiply the gravity of the density of length and cross-sectional area using W = rho * g * L * A and Replace W = rho * g * L * F / Sigma G, L and F are the same for all members. Kind that arent W = G * L * H * (Rho / Sigma) to classify materials, compare their rates of density of elasticity. Those who have a high value of Rho / SIGMA weigh more. People with low levels of Rho / SIGMA weigh less.

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